The large cube is made up of small cubes each with an edge of 4 units. What is the surface area of the resultant cube, if one cube in the middle of the top row is removed?
Answers
Answer:
Look! When you remove that cube, you’re taking away 3 faces, but you’re also exposing 3 more previously unexposed faces! And those newly exposed faces have the exact same areas as the faces you took away. So the surface area, amazingly enough, remains the same.
You’ve got a 3\times 3\times 3 cube there. The original area of each face was 9, and of course all cubes have 6 faces. So the original cube had a surface area of 54.
When you remove the corner piece, you’ve got 54 – 3 + 3 = 54.
Does that help?
Step-by-step explanation:
Look! When you remove that cube, you’re taking away 3 faces, but you’re also exposing 3 more previously unexposed faces! And those newly exposed faces have the exact same areas as the faces you took away. So the surface area, amazingly enough, remains the same.
You’ve got a 3\times 3\times 3 cube there. The original area of each face was 9, and of course all cubes have 6 faces. So the original cube had a surface area of 54.
When you remove the corner piece, you’ve got 54 – 3 + 3 = 54.
Does that help? if yes make me brainlist
Answer:
The bigger cube will have 3 small cubes on each side.
so, side of bigger cube = 3 x 4=12units.
Total Surface area of bigger cube=6(12)^2
= 864 sq units
Now, when the middle piece is removed an area of 4×4 is removed.And increase an area of 5(4)^2
so, after removing the middle piece the area of cube = 864 - 16 + 80 = 928 sq unit