Math, asked by mahal16072005, 11 hours ago

The large hand of a clock is 42cm long. How many centimeters does its extremity move in20 minutes? (a) 80cm (b)88cm (c)18cm (d) 28cm​

Answers

Answered by Anonymous
54

Measurement of angles

We know that the minute hand rotates a full circle in 60 minutes. That is it does 360 degrees in 60 minutes or we can say that, In one rotation, a minute hand or large hand of a clock covers 360 degrees in 60 minutes. i.e. 360 degree = 60 minutes = 2π.

So, Angle traced out by the large hand or minute hand in 20 minutes is,

\implies \dfrac{\cancel{360} \times 20}{\cancel{60}} \\ \\ \implies 6 \times 20 \\ \\ \implies 120^\circ

Therefore, in 20 minutes it makes 120° = 2π/3.

Now we have the length of large hand of a clock and the length of large hand of a clock represents the radius of a circle.

The length of curve of angle θ and radius r is given by,

\implies \boxed{\bf{l = r \theta}}

where, l is the distance covered by the tip of a minute hand, θ is the angle in radian and r is the length or radius of the minute hand.

By substituting the known values in the formula, we get:

\implies l = 42 \times \dfrac{2 \pi}{3} \\ \\ \implies l = \cancel{42} \times \dfrac{2 \times 22}{3 \times \cancel{ \: 7 \: }} \\ \\ \implies l = \cancel{ \: 6 \: } \times \dfrac{2 \times 22}{ \cancel{ \: 3 \: }} \\  \\ \implies l = 2 \times 2 \times 22 \\  \\ \implies \boxed{\bf{l = 88}}

Hence, the distance moved by the extremely of the large hand is 88cm.

Answered by jaswasri2006
48

The Distance moved by the Minute Hand in 20 minutes is 88 cm.

Explanation

For the Explanation, refer the given attachment above.

Formula's used :

Length = radius * angle

l = rθ

Attachments:
Similar questions