The large of two supplementary angles exceed the smaller by 18 degree find them
Answers
Answered by
10
hey buddy!!
Here is your answer;
➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡
⭐⭐⤵
let the angle be x
other angle (it's supplement) =( 180-x)
x+18= (180-x)
2x = 162
x = 162/2 = 81
other angle(its supplement) = 180- x => 180-81 => 99
➡hope this helps you deaR ✌✌✌.
Anonymous:
#Nice status
Answered by
7
Answer:
81°, 99°
Step-by-step explanation:
Let the angles be x, x + 18.
Since they are supplementary,
x + (x + 18°) = 180°
2x + 18° = 180°
2x = 162°
x = 81°
Hence, x + 18 = 81 + 18 = 99°
Similar questions