the large of two supplementary angles exceeds thrice the smaller by 20 degree find them
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x = 3y+20
=> x+y=180 [since they are supplementary angles] ---- equation 1
=> 3y+20+y=180
=> 4y=180-160
=> 4y=160
=>y=40
Putting the value of x in equation 1
x+y=180
x+40=180
x=180-40
x=140
Therefore, x=140 and y=40
=> x+y=180 [since they are supplementary angles] ---- equation 1
=> 3y+20+y=180
=> 4y=180-160
=> 4y=160
=>y=40
Putting the value of x in equation 1
x+y=180
x+40=180
x=180-40
x=140
Therefore, x=140 and y=40
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