The larger of the two supplementary angles is 46° more than smaller angle. Find the angles.
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Let smaller angle=x
Larger angle=x+46
ASP
x+x+46=180
2x+46=180
2x=134
x=67
Smaller angle=67
Larger angle=67+46=113
Larger angle=x+46
ASP
x+x+46=180
2x+46=180
2x=134
x=67
Smaller angle=67
Larger angle=67+46=113
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