Question

The larger of two complementary andles exceeds smaller by 18degrees find the angles ?​

Answer 1

Hola mate here is ur ans ;

Given:

The larger of two supplementary angles exceeds the smaller by 18 degrees.

To find:

The measure of both angles.

solution:

Let the larger angle be ‘a’ and the smaller angle be ‘b’.

Given, larger of two supplementary angles exceeds the smaller by 18 degrees.

⇒ a = b + 18

⇒ a - b = 18 ...... (1)The sum of supplementary angles is 180°.⇒a + b = 180.....(2)

Adding the equations 1 and 2 we get,

a-b+a+b=18+180

⇒ 2a = 198

⇒ a = 99°

Put the value of b in eq. 1 to get, 99-b=18⇒ -b=18-99⇒ -b=-81⇒ b=81

Thus, b = 81°

Hence the measure of smaller angle is 81° and larger angle is 99°.

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Answer 2

Step-by-step explanation:

let largest angle be =x

let smaller angle be =y

but

x+y=180

so, smaller angle exceeds by 18

x+y=180

y+18+y=180

2y=180+8

2y=198

y=99

now

x+y=180

x+99=180

x=180-99

x=81