Question

The larger of two complementary angle exceeds the smaller by 18°. Find them.

Answer 1

Let tge angles be x and x+18
x + x + 18=90
2x=90-18
X=72/2
X=36
X+18=36+18=54
The angels are 36 and 54

Answer 2

$<b><u>Complementary angles are the angles which make the sum of 90°. For example, 30° and 60° or 45° and 45° have the sum of 90°. </b></u>$


Let the angle be x

Other angle [its complement] => 90 - x


A/q,

x + 18 = 90 - x

x + x = 90 - 18

2x = 72

x = $\dfrac{72}{2}$

x = 36



Smaller angle => x => 36°

Larger angle => 90 - x => 90 - 36 => 54°




$\therefore{}$ The angles are 36° and 54°