the larger of two complementary angles exceeds the smaller by 36 degree find them
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QUESTION : the larger of two complementary angles exceeds the smaller by 36 degree find them
WHAT TO DO : FIND THE ANGLES
WE KNOW THAT ;
SUM OF COMPLEMENTARY ANGLES = 360°
LET THE ANGLES BE x AND x + 36°
=> x+x+36=360°
=> 2x+36°=360°
=>2x=360-36
=>x=324÷2
=>x = 162°
1st angle = x = 162°
2nd angle = 36+x = 162 + 36= 198°
ANSWER : 162° , 198°
HOPE IT HELPS !
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