Question

the larger of two complementary angles exceeds the smaller by 18 degrees find them.

Answer 1

Answer:36° and 54°

Step-by-step explanation:

Let the smaller angle be x

Therefore the larger angle is x+18,

∵They are complementary

x+x+18=90°

2x=90-18

2x=72

x=72/2

x=36

Therefore the two angles are 36° and 54°

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Answer 2

Given,

The larger of two complementary angles exceeds the smaller by 18 degrees.

To Find,

The angles =?

Solution,

We can find the two complementary angles as follows:

It is given to us that the larger of two complementary angles exceeds the smaller by 18 degrees.

Let the smaller angle be equal to x. Then the larger angle will be x + 18.

Two angles are said to be complementary if their sum is equal to 90 degrees.

Therefore,

$x + x + 18 = 90$

$2x + 18 = 90$

$2x = 90 - 18$

$2x = 72$

$x = \frac{72}{2} = 36$ degrees

The smaller angle is 36 degrees. The larger angle will be,

$x + 18 = 36 + 18 = 54$ degrees

Hence, the two complementary angles are 36 degrees and 54 degrees.