The larger of two concentric circles has radius 8cm.If a chord of the larger circle is tangent to the smaller circle has length 4√14 cm,what is the radius of smaller circle
Answers
Answer:
6cm
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Answer:
The radius of smaller circle is 2√2 cm .
Step-by-step explanation:
Given as :
The radius of the larger circle = R = 8 cm
Let The radius of the smaller circle = r cm
The tangent of the smaller circle is the chord of the larger circle
The measure of the chord of the larger circle = 4√14 cm
According to question
From figure ,
A concentric circle with center O
The radius of smaller circle = OE = r cm
The radius of the larger circle = OC = OD = R = 8 cm
The length of the chord of the larger circle = CD = 4√14 cm
So, The radius of larger circle make right angle at center O
From the property of right angled triangle
OD² = OE² + ED²
∵ CD = 4√14 cm
∴ ED = 2√14 (ED is half of CD)
So, OD² = OE² + ED²
Or, 8² = OE² + (2√14)²
Or, 64 - 56 = OE²
Or, OE² = 8
∴ OE = √8
i.e OE = 2√2 cm
So, The radius of smaller circle = OE = 2√2 cm
Hence, The radius of smaller circle is 2√2 cm . Answer