Question

the larger of two supplementary angels exceeds thrice the smaller by 20degree .find them.​

Answer 1

refer to the attachment for the answer

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Answer 2

Answer :-

The angles are 140° and 40°.

Solution :-

Let the smaller angle be x°

Given

Larger angle = exceeds thrice the smaller by 20°

= 3(x) + 20

=(3x + 20)°

(3x + 20) + x = 180°

(Because given angles are supplementary)

3x + 20 + x = 180

4x + 20 = 180

4x = 180 - 20

4x = 160

x = 160/4

x = 40

Smaller angle = x = 40°

Larger angle = (3x + 20)

= 3(40) + 20

= 120 + 20

= 140°

Therefore the angles are 140° and 40°.

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