the larger of two supplementary angle exceeds the smaller by 18 degree find its radius? ?
Answers
Answered by
3
hi...its an easy question ...
Let first angle = x
And second number = y
As both angles are supplementary so that sum will 180
x + y = 180
x = 180 - y ... (1)
Difference is 18 degree so that
x – y = 18
Plug the value of x we get
180– y – y = 18
- 2 y = -162
y = -162/-2
y = 81
Plug the value back in equation first we get
x = 180 – 81 = 99
if u like mark brainlisst to others answer
Let first angle = x
And second number = y
As both angles are supplementary so that sum will 180
x + y = 180
x = 180 - y ... (1)
Difference is 18 degree so that
x – y = 18
Plug the value of x we get
180– y – y = 18
- 2 y = -162
y = -162/-2
y = 81
Plug the value back in equation first we get
x = 180 – 81 = 99
if u like mark brainlisst to others answer
priya146:
thanks
Answered by
13
Step-by-step explanation:
HLW MATE HERE IS YOUR CORRECT ANSWER.......
Let the larger angle be 'x' and the smaller one be 'y'
ATQ,
x =y +18 ---------------------(1)
We know that, sum of supplementary angles =180°
x+y=180°---------------------(2)
SUBSTITUTE x=y+18 in eq (2)
y+18+y=180°
2y=180-18
2y=162
y=162/2
✓y=81
x=81+18
=99
THEREFORE,
THE ANGLES ARE 81 AND 99
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