The larger of two supplementary angle s exceeds the smaller by 18 degrees .Find them.
Answers
Step-by-step explanation:
let X and y be the two supplementary angles
= X*y = 180......(1)
given that one angle is greater than other by 18
= x= y +18.....(2)
putting value of x in the equation first
= y+18+y= 180
=2y = 162
= y=162/2
= y= 81
= x= y+18
= x= 81+18
= x= 99
two supplementary angles are 99 and 81
Given :-
• The larger of two supplementary angles exceeds the smaller by 18 degrees .
To Find :-
• What are the angles?
Solution :-
Let the larger angle be x and the smaller angle be y.
As per question :-
Given that,
The larger of two supplementary angles exceeds the smaller by 18 degrees .
We know, the sum of supplementary angles is 180°
Therefore,
x +y = 180°.............eq(1)
x - y = 18............... eq(2)
Find the value of x from eq(1)
x + y = 180°
⟼ x = 180° -y.......... eq(3)
Now, put the value of x in eq(2)
x -y = 18
⟼ 180° - y -y = 18
⟼ 180° - 2y = 18
⟼ -2y = -162
⟼ y = 81°
Hence, the smaller angle is = 81°
After putting the value of y in eq(3), we get
x = 180° - y
⟼ x = 180° - 81°
Therefore, the larger angle is = 99°
And the smaller angle is = 81°