Question

The larger of two supplementary angles exceed the smaller by 38°.The two angels are

Answer 1

Let the two angle be /x and /y
according to given condition-
/x+/y = 180 ----(1)
/x = /y + 18 -----(2)
substituting the value of (2) in (1)
(1) - /x+/y = 180
- (/y+18)+/y = 180
- 2/y+ 18 = 180
-2/y = 162
-/y= 81

substituting the value of y in (2)
/x=/y+18
/x=81+18
/x=99

Answer 2

let the larger angle be x and smaller is x-38*
now
x+x-38*=180*
2x=180*-38*
2x=142
x=142/2
x=71
another angle will be 71-38=33