the larger of two supplementary angles exceeds smaller by 180*. write pair of linear equtation
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Answer:
Let the larger angle be ‘a’ and the smaller angle be ‘b’.
Given, larger of two supplementary angles exceeds the smaller by 18 degrees.
⇒ a = b + 18
⇒ a - b = 18 ...... (1)The sum of supplementary angles is 180°.⇒a + b = 180.....(2)
Adding the equations 1 and 2 we get,
a-b+a+b=18+180
⇒ 2a = 198
⇒ a = 99°
Put the value of b in eq. 1 to get, 99-b=18⇒ -b=18-99⇒ -b=-81⇒ b=81
Thus, b = 81°
Hence the measure of smaller angle is 81° and larger angle is 99°.
Answered by
1
Answer:
x+y=180
x-y=180
where x is larger & Y is smaller
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