the larger of two supplementary angles exceeds the smaller by 18 degrees find them
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0
Answer:
LET THE SMALLER ANGLES BE'X'
THERFORE LARGER ANGLE IS X+18
=X+X+18=90
2X+18=90
2X=90-18
2X=72
X=72/2
=X=36
SMALLER ANGLE= 36
LARGER ANGLE= X+18=36+18=54
Answered by
3
let the two angle be /x and /y
according to given condition-
/x+/y = 180 ----(1)
/x = /y + 18 -----(2)
substituting the value of (2) in (1)
(1) - /x+/y = 180
- (/y+18)+/y = 180
- 2/y+ 18 = 180
-2/y = 162
-/y= 81
substituting the value of y in (2)
/x=/y+18
/x=81+18
/x=99
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