the larger of two supplementary angles exceeds the smaller by 18 degrees find them
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Let the larger angle be 'x' and the smaller one be 'y'
ATQ,
x =y +18 ---------------------(1)
We know that, sum of supplementary angles =180°
x+y=180°---------------------(2)
SUBSTITUTE x=y+18 in eq (2)
y+18+y=180°
2y=180-18
2y=162
y=162/2
✓y=81
x=81+18
=99
THEREFORE,
THE ANGLES ARE 81 AND 99
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