Question

the larger of two supplementary angles exceeds the smaller by18 degrees. find them​

Answer 1

Answer:

Smaller angle is 81°

Larger angle is 99°

Step-by-step explanation:

Let the smaller angle be X and the larger angle will be (x+18).

According to the Condition,

x + (x+18) = 180°

2x+18 =180

2x = 180-18

2x = 162

$x = \frac{162}{2}$

x = 81°

Now,

Smaller angle = x = 81°

Larger angle = (x+18) = (81+18) = 99°

Thank you and hope it helps.

Answer 2

let the two angle be /x and /y

according to given condition-

/x+/y = 180 ----(1)

/x = /y + 18 -----(2)

substituting the value of (2) in (1)

(1) - /x+/y = 180

- (/y+18)+/y = 180

- 2/y+ 18 = 180

-2/y = 162

-/y= 81

substituting the value of y in (2)

/x=/y+18

/x=81+18

/x=99