Question

The larger of two supplementary angles exceeds the smaller by 18°. Find the angles.​

Answer 1

Answer:

Let the angle be x

other angle (it's supplement) =( 180-x)

x+18= (180-x)

2x = 162

x = 162/2 = 81

other angle(its supplement) = 180- x => 180-81 => 99

hope this helps

Answer 2

✪ $\huge{\red{\underline{\overline{\mathbf{Question}}}}}$ ✪

→The larger of two supplementary angles exceeds the smaller by 18°. Find the angles.

✪ $\huge{\green{\underline{\overline{\mathbf{Answer}}}}}$ ✪

⇒Given:

• Larger angle - Smaller angle = 18°
• The angles are Supplement

⇒To Find:

• Both angles

⇒Solution:

Let larger angle i.e. $\angle 1 = x$

$\therefore$ smaller angle = x-18

⇒$\angle 1 + \angle 2 =180^{\circ}$

⇒$x+x-18^{\circ}=180^{\circ}$

⇒$2x=198^{\circ}$

⇒$x=99^{\circ}$

⇒Smaller angle = 81°

Angles are :-

⇒$\huge{\pink{\overbrace{\underbrace{99^{\tiny{\circ}},81^{\tiny{\circ}}}}}}$

★━★━★━★━★━★━★━★━★━★━★

▂ ▄ ▅ ▆ ▇ █⚡ ᗩᖇƳᗩᑎ ⚡█ ▇ ▆ ▅ ▄ ▂

★━★━★━★━★━★━★━★━★━★━★