the larger of two supplementary angles exceeds the smaller by 18 .find the angles
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Answer:
Step-by-step explanation:
let the angle be x
then smaller=x-18
therefore
x+x-18=180
2x-18=180
2x=198
x=99=larger angle
x-18=81=smaller angle
Answered by
52
Given :
- the larger of two supplementary angles exceeds the smaller by 18.
To Find :
- The Angles
Solution :
⟶ The larger of two supplementary angles be x
⟶ Then Other angle will be 180° - x
According to the Question :
⟹ x - (180° - x) = 18°
⟹ x - 180° + x = 18°
⟹ x + x = 18° + 180°
⟹ x + x = 198°
⟹ 2x = 198°
⟹ x = 198° / 2
⟹ x = 99°
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Verification :
➟ x - (180° - x) = 18°
➟ x - 180° + x = 18°
➟ 99° - 180° + 99° = 18°
➟ - 81° + 99° = 18°
➟ 18° = 18°
Hence Verified
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Thus , The Angles are 99° and 180° - x = 180° - 99 = 81°
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