Question

the larger of two supplementary angles exceeds the smaller by 18 degrees find them

Answer 1

let smaller angle be x and larger be y
then according to question
y = x + 18
Now
x + 18 + x = 180°. ( sum of supplementary angles is 180°)
2x = 180°-18
x = 152/2
x = 76°

Another angle 76° + 18 = 94°

Answer 2

let one angle be x and other y
 smaller is y and larger is x

  x + y =180.....1eq
 2x=18y..................2x-18y=0........eq2

               multiplying 1 by 2........we get.................2x+2y=360...........eq3

                    on subtracting 3 and 2 we get

                

                  2x+2y=360
                   2x-18y=0
                 -     +     = - 
                          20y= 360 

        y= 18       
please check the answer ......if it is wrong do tell me .........