Question

The larger of two supplementary angles exceeds the smaller by 18°. Find the angles.

Answer 1

Hi ,

Let two angles be x , y ( x > y )

Given x , y are supplementary ,

x + y = 180° ----( 1 )

Also given that

the larger of two supplementary angles

exceeds the smaller by 18°

x - y = 18° -----( 2 )

add equations ( 1 ) and ( 2 ) , we get

2x = 198

x = 198/2

x = 99°

Put x = 99° in equation ( 1 ) , we get

99° + y = 180°

y = 180° - 99°

y = 81°

Therefore ,

The larger angle = x = 99°

and

smaller angle = y = 81°

I hope this helps you.

: )

Answer 2

Answer:

Step-by-step explanation:

Let the smaller angle be x,

Then the largest angle is x+18,

x+x+18=90

2x+18=90

2x=90-18

2x=72

x=72/2

x=36

Therefore,

The smaller angle be x,

=36 degree

Then the largest angle is x+18,

=(36 +18)degree

=54 degree

Mark as brainliest