Question

The larger of two supplementary angles exceeds the smaller by 28° find the angles

Answer 1

Answer:

$\red { Required \: angles \:are }$

$\green { 104 \degree \:and \:76\degree}$

Step-by-step explanation:

$Let \: x \:and \:(180-x) \:are \: two \\supplementary \:angles$

/* According to the problem given ,

$x - (180-x) = 28\degree$

$\implies x - 180 + x = 28$

$\implies 2x = 28 + 180$

$\implies 2x = 208$

$\implies x = \frac{208}{2} = 104 \degree$

Therefore.,

$\red { Required \: angles \:are }$

$\green { one \:angle (x) = 104 \degree }$

$\green { Second \:angle (180-x) = 180-104= 76 \degree }$

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