Question

The larger of two supplementary angles exceeds the smaller by 28 degree find the angels

Answer 1

$\textbf{ \underline{ \huge{ Hello Mate! }}}$

Let the smallest of two supplementary angles be x. As per given in question. Larger angle exceeds the smaller angle by 28°.

This means that another angles is x + 28°

Sum of supplimentary angles is 180°

x + ( x + 28° ) = 180°

x + x = 180° - 28°

2x = 152°

x = 152° / 2

x = 76°

So largest angle = 76° + 28° = 104°.

$\textsf{ \red{ Smallest and largest angle = 76°, 104° respectively }}$

$\textbf{ Have great future ahead! }$