the larger of two supplementary angles exceeds the smaller by 18 degrees find them
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Answered by
8
Heyya there
Here is ur answer
The larger of two supplementary angles exceeds the smaller by 18 degrees. Find them.
Let first angle = x
And second number = y
As both angles are supplementary so that sum will 180
x + y = 180
x = 180 - y ... (1)
Difference is 18 degree so that
x – y = 18
Plug the value of x we get
180– y – y = 18
- 2 y = -162
y = -162/-2
y = 81
Plug the value back in equation first we get
x = 180 – 81 = 99
Hence angles are 81 and 99
Hope it may helps you
Here is ur answer
The larger of two supplementary angles exceeds the smaller by 18 degrees. Find them.
Let first angle = x
And second number = y
As both angles are supplementary so that sum will 180
x + y = 180
x = 180 - y ... (1)
Difference is 18 degree so that
x – y = 18
Plug the value of x we get
180– y – y = 18
- 2 y = -162
y = -162/-2
y = 81
Plug the value back in equation first we get
x = 180 – 81 = 99
Hence angles are 81 and 99
Hope it may helps you
sanjith78:
hi
Answered by
26
Let the larger angle be x°
and the smaller angle be y °
ATQ
x°+y° = 180 ----------------i
x-y = 18 -----------------ii
=> x= 18+y
Substituting the value of x in (i)
18+y+y = 180
=> 18+2y = 180
=> 2y = 180-18
=> y = 162/2
=> y = 81°
x = 18+y
= 18+81
= 99°
Therefore, the larger angle is 99°
and the smaller angle is 81°
HOPE IT HELPS YOU !!!
and the smaller angle be y °
ATQ
x°+y° = 180 ----------------i
x-y = 18 -----------------ii
=> x= 18+y
Substituting the value of x in (i)
18+y+y = 180
=> 18+2y = 180
=> 2y = 180-18
=> y = 162/2
=> y = 81°
x = 18+y
= 18+81
= 99°
Therefore, the larger angle is 99°
and the smaller angle is 81°
HOPE IT HELPS YOU !!!
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