Question

the larger of two supplementary angles exceeds the smaller by 18 degree find them​

Answer 1

let the angles be x and x+18°

A/Q

x+x+18°=180°

2x+18°=180°

2x=162°

x=81°

x+18°=81°+18°=99°

hence two angles are 81° and 99°

Answer 2

Step-by-step explanation:

HLW MATE HERE IS YOUR CORRECT ANSWER.......

Let the larger angle be 'x' and the smaller one be 'y'

ATQ,

x =y +18 ---------------------(1)

We know that, sum of supplementary angles =180°

x+y=180°---------------------(2)

SUBSTITUTE x=y+18 in eq (2)

y+18+y=180°

2y=180-18

2y=162

y=162/2

✓y=81

x=81+18

=99

THEREFORE,

THE ANGLES ARE 81 AND 99