Math, asked by dadu60, 1 year ago

the largest 2 digit number that is divisible by both 3 and 10 is??

Answers

Answered by Anonymous
13
hey buddy!! here's your answer...

the largest 2 digit number divisible by both 3 and 10 is ... ✴️ 90.

hope it helps !! ✌️❤️

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Answered by payalchatterje
0

Answer:

The largest 2 digit number that is divisible by both 3 and 10 is 90.

Step-by-step explanation:

Here we want to find largest 2 digit number that is divisible by both 3 and 10.

We know, largest two digit number is 99.

Now 3 and 10 don't have any common divisors.

So,largest 2 digit number that is divisible by both 3 and 10 means largest 2 digit number that is divisible by 30.

Now we are dividing 99 by 30 and get 3 as quotient and 9 as remainder.

So (99-9)=90 is the largest 2 digit number that is divisible by both 30.

Therefore we can say,

The largest 2 digit number that is divisible by both 3 and 10 is 90.

This is a problem of Algebra.

Some important formulas of Algebra.

(a + b)² = a² + 2ab + b²

(a − b)² = a² − 2ab − b²

(a + b)³ = a³ + 3a²b + 3ab² + b³

(a - b)³ = a³ - 3a²b + 3ab² - b³

a³ + b³ = (a + b)³ − 3ab(a + b)

a³ - b³ = (a -b)³ + 3ab(a - b)

a² − b² = (a + b)(a − b)

a² + b² = (a + b)² − 2ab

a² + b² = (a − b)² + 2ab

a³ − b³ = (a − b)(a² + ab + b²)

a³ + b³ = (a + b)(a² − ab + b²)

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