the largest 3- digit number divisible by 19
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So subtract 12 from 1000 to get the largest 3-digit number divisible by 19. 1000−12=988 is our required number.
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largest 3-digit number divisible by 19 subtract 11 from 999. ⇒999−11=988 is our required number. When 988 is divided by 19, the quotient is 52 and the remainder is obviously zero. Hence, the correct option is Option A, 988.
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