Question

The largest 4 digit even positive integer and the smallest 3 digit odd negative integer? Sum

Answer 1

Answer:

9897

Step-by-step explanation:

largest 4 digit even positive integer=9998.

and smallest 3 digit odd negative integer = -101.

their sum=9998+(-101)=9998-101=9897.

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Answer 2

Answer:

Concept:

Step-by-step explanation:

Given:

Largest 4 digit integer and smallest 3 digit negative integer

To find:

Sum of 4 digit largest even positive integer and smallest 3 digit odd negative integer

Solution:

• Largest 4 digit even positive integer  - $9998$

• Largest  4 digit integer is $9999$. It is given as
• even integer
• . so the
• preceding number
• of $9999$ is taken into account.

• Smallest 3 digit negative integer - $-999$

The smallest 3 digit number is $101$. But it is given as negative integer and so   $-999$ is  considered .

• Finding sum of the integers found from the given statement

          $=9998+(-999)$

           $=8999$

Hence, the sum of largest 4 digit even positive integer and the smallest 3 digit odd negative integer is $8999$

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