Question

The largest 4 digit number which when divided by 18 leaves a remainder of 6

Answer 1

First we have to find the number which is divided by all the given numbers i.e 6,9,12,17

For that we have to find the LCM of those numbers.

The LCM of 6,9,12,17 is 612.

Now we shall find the largest 4-digit number which is divisible by 6,9,12,17 .

For that we have to find the largest 4-digit multiple of 612.

If we consider (612*17)= 10404 (since it is a 5-digit number we should reduce the multiple )

i.e (612*16)

=>9792

so it is the largest possible 4-digit number which is divisible by all the given numbers

But the question is to find the number which leaves a remainder of 2 when it is divided by all those numbers

So for that we have to add 2 to the obtained number…

so the answer is (9792 +2)

=> 9794