The largest angle in a triangle is 6 times the smallest, and the difference between them is 100degree.
The measure of the second largest angle of the triangle will be
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40
Let the angles be a−d,a,a+d, where a and d are first term and common difference respectively.
∴a−d+a+a+d=180 (∵sum of angles of trianlge)
3a=180⇒a=60
Also, a+d=2(a−d) (Given)
⇒60+d=2(60−d)
⇒3d=60⇒d=20
Therefore, angles are 60−20,60,60+20 i.e.40,60,80
Difference =80−40=40
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