Question

The largest angle of a triangle is equal to sum of the other to angles. The smallest angle is 1/4 of the largest. Find the angles of the triangle

Answer 1

NOW WE HAVE,
<A=90°
<B=3/4<A..........................from(3)
<B=3/4×90
<B=67.5°
<C=1/4×90°
<C=22.5
THEREFORE, THE ANGLES OF THE GIVEN TRIANGLE ARE 90°,67.5°&22.5°
HOPE THIS HELPS YOU!!!

Answer 2

Answer:

Step-by-step explanation:Let A,B&c be the angles of Triangle

∠A be the largest angle

∠A+∠B+∠C= 180° (angle sum prop.)

A/q

∠A=1/4∠c

∠B=4∠A+∠A/4

∠B=3/4∠A

∠A+∠B+∠C= 180°

∠A+3/4∠A+1/4∠A= 180°

4∠A+3∠A+∠A/4=180°

8∠A= 180×4

∠A=180×4/8

∠A=90°

∴ ∠B=3/4×90

        =67.5

∠C=1/4×90

     = 22.5

∴∠A=90°,∠B=67.5°&∠C=22.5°