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The largest angle of a triangle is equal to the sum of the other two angles. If the smallest angle is 1/3 of the largest angle then the angles of a triangle is​

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Answered by Anonymous
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Answer:

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Under the Permanent Settlement, the zamindars were given the charge of collecting revenue from the peasants and paying it to the Company. But in the mahalwari system this charge was given to the village headman.

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Answered by SANDHIVA1974
2

Given:

The largest angle of a triangle is equal to the sum of the other two angles. The smallest angle is 1/3 of the largest angle.

Need to Find: Angles of Triangle.

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❍ Now, let us assume that tLargest angle as x, Smallest angle as x/3 and another angle as y

1st equation :-

\\:\implies\quad\sf{x = \dfrac{x}{3} + y}

\\:\implies\quad\sf{x = x +\dfrac{3y}{3}}

\\:\implies\quad\sf{3x = x + 3y}

\\:\implies\quad\sf{2x = 3y}

\\:\implies\quad\sf{2x - 3y = 0\qquad\qquad\left\lgroup\begin{matrix}\sf{{eq}^{n}} \: (I) \end{matrix}\right\rgroup\]}

Now,

2nd equation :-

As we know that sum of all angles in a triangle is 180°.

\\:\implies\quad\sf{x + x/3 +y = {180}^{o}}

\\:\implies\quad\sf{3x + x + 3y = {540}^{o}}

\\:\implies\quad\sf{4x + 3y = {540}^{o}\qquad\quad\left\lgroup\begin{matrix}\sf{{eq}^{n}} \: (II) \end{matrix}\right\rgroup\]}

Adding equation (i) & (ii) we get

\\:\implies\quad\sf{6x = {540}^{o}}

\\:\implies\quad\sf{x =\dfrac{540}{6}}

\\:\implies\quad\underline{\boxed{\pmb{\frak{x = {90}^{o}}}}}

Now, putting the value of x = 90° in Equation (i) we get

\\:\implies\quad\sf{{180}^{o} -3y = 0}

\\:\implies\quad\sf{-3y = {-180}^{o}}

\\:\implies\quad\sf{y =\dfrac{{180}^{o}}{3}}

\\:\implies\quad\underline{\boxed{\pmb{\frak{y = {60}^{o}}}}}

And ,

\\:\implies\quad\sf{Smallest\: angle =\dfrac{x}{3}}

\\:\implies\quad\sf{Smallest\: angle =\dfrac{90}{3}}

\\:\implies\quad\underline{\boxed{\pmb{\frak{Smallest\: angle={30}^{o}}}}}\\

\qquad\leadsto Hence, the angles of triangles are 90° , 60° & 30°.

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