Question

The largest angle of a triangle is twice the sum of the other two. The smallest is one-sixth of the largest. determine all the angles in degrees.​

Answer 1

Answer:

let largest angle is x°

smallest angle is x/6°

another is (180-x-x/6)°=(180-7x/6)°

so, 2(180-7x/6+x/6)=x

=> 2(180-x)=x

=> 360-2x=x

=> 360=x+2x

=> 360=3x

=> x=360/3=120

so largest angle is 120°

smallest angle =120/6°=20°

another angle=(180-120-20)°=(180-140)°=40°