the largest coefficient in the expansion of (1+x)^30 is
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Answer:
Largest coefficient ='x'
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Total number of terms=n+1, so 30+1=31.
Now to find the greatest coefficient
We need the highest power of x, which is the middle term.
Since the total number of terms is 31 which is odd then, middle term = n+1/2=
31+1/2=16.
16th term is the highest coefficient so by using Tr+1=nCr×X^n-r×Y^r, we have
T15+1=30C15×X^15×1^15
T16=30C15×X^15.
Therefore 30C15 is the greatest coefficient.
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