Math, asked by asksandeepraj2273, 1 month ago

The largest four-digit number, which is divisible by each of the numbers 12, 18, 21 and 28, is :

Answers

Answered by tanishpednekar
0

Answer:

9828

Step-by-step explanation:

Required number is divisible by the L . C . M of 12, 18, 21, 28 i.e 252.

Now, greatest number of four digits = 9999

On dividing 9999 by 252, the remainder is 171

∴ Required number = (9999 - 171) = 9828.

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