Question

the largest integer 'n' such that(n+10)divides n cube+100is

Answer 1

Dividing +100 by n+10 with the help of long division we get −10n+100 as a quotient and - 900 as a remainder we know that divisor * quotient +remainder=dividend n+10(−10n+100)-900 =+100.....1 dividing equation 1 by n+10 we get +100/ n+10= (−10n+100) -900 /n+10 to maximize 900/n+10 should be minimise to lowest integer which in this case is 1 900=n+10 n=890