The largest integer that is a divisor of (n + 1)(n+3) (n + 5)(n+7) (n + 9) for all positive even integers n is equal to :--
(a) 3
(b) 5
(c) 11
(d) 15
Answers
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- 11
- 11 is our true answer.
- 1(n+1)
- 1+2=3(n+3)
- 3+2=5(n+5)
- 5+2=7(n+7)
- 7+2=9(n+9)
- (n+1),(n+3),(n+5),(n+7),(n+9) into 1,3,5,7,9 are digit is odd number and next odd number is 11 so our answer is11
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