The largest no. which divides 258 and 1249 leaving remainder 9 and 7 respectively
Answers
Answered by
1
a number divides 258 leaving remainder 9
therefore,258-9=249
SAME FOR 1249
1249-7=1242
HCF 249 AND 1242=3
therefore ur answer is 3
HOPE IT HELPS
therefore,258-9=249
SAME FOR 1249
1249-7=1242
HCF 249 AND 1242=3
therefore ur answer is 3
HOPE IT HELPS
Answered by
0
the correct answer is 3
Similar questions