The largest no. which divides 70 and 125 leaving remainder 5 and 8 respectively is?
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13
Since, 5 and 8 are remainders of 70 and 125 respectively. Thus, after subtracting these remainders from the numbers, we have the number 65 = (70 - 5), 117 = (125 - 8), which is divisible by the required number. Hence, 13 is the largest number which divides 70 and 125, leaving remainders 5 and 8
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Step-by-step explanation:
Number when divides 70 and 125 leaves remainders 5 and
8, then
70−5=65
125−8=117
then HCF of 65 and 117 is
65=5×13
117=3×3×13
Hence, HCF of 65 and 117 is 13.
13 is the largest number which divides 70 and 125 and leaves remainders 5 and 8.
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