The largest no. which divides 70 and 125 leaving remainder 5,8
Answers
Answer:
Step-by-step explanation:
Thinking process :-
First , we subtract the remainders 5 and 8 from corresponding numbers respectively and then HCF of resulting numbers by using Euclid's division algorithm, which is the required largest number.
Solution:-
Since, 5 and 8 are remainders of 70 and 125 respectively.Thus, after subtracting these remainders from the numbers, we have the number 65 = (70 - 5), 117 = (125 - 8), which is divisible by the required number.
Now, required number = HCF of 65, 117 [for the largest number]
⇒ 117 = 65 × 1 + 52 [∵ dividend = divisor × quotient + remainder]
⇒ 65 = 52 × 1 + 13
⇒ 52 = 13 × 4 + 0
∴ HCF = 13
Hence, 13 is the largest number which divides 70 and 125, leaving remainder 5 and 8
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Answer:
Answer:- 13
Step-by-step explanation:
= 70 - 5 = 65
= 125 - 8 = 117
Now, by Euclid's division method, find the HCF of 65 and 117
= 117 = 65 * 1 + 52
= 65 = 52 * 1 + 13
= 52 = 13 * 4 + 0
= HCF = 13