Math, asked by balaramabarik77, 4 months ago

The largest number of 5 digit which when divided by 16,24,30,36 leaves remainder 10 in each case?
(Any short cut method can tell me)​

Answers

Answered by devimadhu31575
10

Answer:

Yes

With calculator

Mark me brainliest

Answered by rkcomp31
2

Answer:

99370

Step-by-step explanation:

LCM of 16,24,30,36=2^4*3^2*5

=16*9*5

=720

The no is leaving remainder 10 in each case

So the no is in form 720x + 10

Now the greatest 5 digit no=99999

now 99999 can be written as:

99999= 138*720+ 10+ 629

Thus the required number

=138*720+10

=99370

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