Question

The largest number of four digits which is exactly divisible by 18 25 and 35

Answer 1

$\textbf{Answer :}$

The numbers are 18, 25 and 35

Now,

18 = 2 × 3 × 3

25 = 5 × 5

35 = 5 × 7

So, the required LCM be

= 2 × 3 × 3 × 5 × 5 × 7

= $\textbf{3150}$,

which is the required number.

#$\textbf{MarkAsBrainliest}$

Answer 2

Answer:

The number 9450 is the largest number of four digits which is exactly divisible by 18 25 and 35.

Step-by-step explanation:

The numbers are 18, 25 and 35 .

The factors of given numbers are

$18=2\times 3\times 3$

$25=5\times 5$

$35=5\times 7$

So, the required LCM of given numbers is

$2\times 3\times 3\times 5\times 5\times 7=3150$

It is the smallest number of four digits which is exactly divisible by 18 25 and 35.

The largest number of four digits is 9999.

Divide 9999 by 3150.

$\frac{9999}{3150}=3+\frac{549}{3150}$

The remainder is 549. Subtract the remainder from 9999.

$9999-549=9450$

Therefore the number 9450 is the largest number of four digits which is exactly divisible by 18 25 and 35.