Math, asked by kimdelivenge3142, 1 year ago

The largest number of four digits which is exactly divisible by 18 25 and 35

Answers

Answered by MarkAsBrainliest
46
\textbf{Answer :}

The numbers are 18, 25 and 35

Now,

18 = 2 × 3 × 3

25 = 5 × 5

35 = 5 × 7

So, the required LCM be

= 2 × 3 × 3 × 5 × 5 × 7

= \textbf{3150},

which is the required number.

#\textbf{MarkAsBrainliest}
Answered by DelcieRiveria
40

Answer:

The number 9450 is the largest number of four digits which is exactly divisible by 18 25 and 35.

Step-by-step explanation:

The numbers are 18, 25 and 35 .

The factors of given numbers are

18=2\times 3\times 3

25=5\times 5

35=5\times 7

So, the required LCM of given numbers is

2\times 3\times 3\times 5\times 5\times 7=3150

It is the smallest number of four digits which is exactly divisible by 18 25 and 35.

The largest number of four digits is 9999.

Divide 9999 by 3150.

\frac{9999}{3150}=3+\frac{549}{3150}

The remainder is 549. Subtract the remainder from 9999.

9999-549=9450

Therefore the number 9450 is the largest number of four digits which is exactly divisible by 18 25 and 35.

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