The largest number of four digits which is exactly divisible by 18 25 and 35
Answers
Answered by
46
The numbers are 18, 25 and 35
Now,
18 = 2 × 3 × 3
25 = 5 × 5
35 = 5 × 7
So, the required LCM be
= 2 × 3 × 3 × 5 × 5 × 7
= ,
which is the required number.
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Answered by
40
Answer:
The number 9450 is the largest number of four digits which is exactly divisible by 18 25 and 35.
Step-by-step explanation:
The numbers are 18, 25 and 35 .
The factors of given numbers are
So, the required LCM of given numbers is
It is the smallest number of four digits which is exactly divisible by 18 25 and 35.
The largest number of four digits is 9999.
Divide 9999 by 3150.
The remainder is 549. Subtract the remainder from 9999.
Therefore the number 9450 is the largest number of four digits which is exactly divisible by 18 25 and 35.
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