The largest number of molecules are present in
a) 44 g of CO2
b) 98 g of H2SO4
c) 36 g H2O
d) 180 g of C6H12O6
Answers
Answer:
[C] 36 G OF H₂O.
Explanation:
1 MOLE OF A SUBSTANCE CONTAIN AVOGADRO NUMBER OF MOLECULES.
1 MOLE CONTAINS : 6.02*10²³ MOLECULES.
[A] 44 G OF CO₂ [ MOLECULAR MASS = 12+2*16
= 12+32
= 44 G ]
1 MOLE OF CO₂ WEIGHS 44 G
THEREFORE 6.02*10²³ MOLECULES IN 44 G OF CO₂
[B] MOLECULAR MASS OF H₂SO₄
= 2*1+32+4*16
= 2+32+64
= 98 G
THEREFORE 98 G OF H₂SO₄ = 1 MOLE = 6.02*10²³ MOLECULES.
[C] MOLECULAR MASS OF H₂O
= 2*1+16
= 2+16
= 18.
1 MOLE = 18 G
X MOLES = 36 G
X = 2 MOLES
1 MOLE CONTAINS 6.02*10²³ MOLECULES
2 MOLES CONTAIN = 6.02*10²³
= 12.04*10²³ MOLECULES.
[D] MOLECULAR MASS OF C₆H₁₂O₆
= 12*6 + 1*12+16*6
= 180 G
1 MOLE OF C₆H₁₂O₆ CONTAINS 6.02*10³ MOLECULES.
THEREFORE MAXIMUM NUMBER OF MOLECULES IN 36 G OF H₂O.
HOPE THIS HELPS.
Answer:
The largest number of molecules are present in a) 44 g of CO2 b) 98 g of H2SO4 c) 36 g H2O d) 180 g of C6H12O6. 1 tq