Question

the largest number that divides 138 and 233 leaving remainder 5 in each case is​

Answer 1

SOLUTION

TO DETERMINE

The largest number that divides 138 and 233 leaving remainder 5 in each case

EVALUATION

Let x is the greatest number that divides 138 and 233 leaving remainder 5 in each case

Since x divides 138 and 233 leaving remainder 5 in each case

Then x will divide 138 - 5 , 233 - 5

So x divides 133 and 228

Now

133 = 7 × 19

228 = 2 × 2 × 3 × 19

HCF = 19

Hence 19 is the largest number that divides 138 and 233 leaving remainder 5 in each case

━━━━━━━━━━━━━━━━

Learn more from Brainly :-

$1.$ If HCF of two numbers be 40 then which of the following cannot be their LCM.

https://brainly.in/question/28609013

2. The HCF and LCM of two numbers are 17 & 1666 respectively. if one of the numbers is 119 find the other

https://brainly.in/question/13812250