Question

The largest number that divides 64 and 72 and leave the remainder 12 and 7 respectively

Answer 1

Answer:

13 is your answer.

Answer 2

Answer:

Remainder of 64 is 12

Remainder of 64 is 12So 64−12

Remainder of 64 is 12So 64−12=52

Remainder of 64 is 12So 64−12=52Remainder of 72 is 7

Remainder of 64 is 12So 64−12=52Remainder of 72 is 772−7

Remainder of 64 is 12So 64−12=52Remainder of 72 is 772−7=65

Remainder of 64 is 12So 64−12=52Remainder of 72 is 772−7=65H.C.F of 52,65

Remainder of 64 is 12So 64−12=52Remainder of 72 is 772−7=65H.C.F of 52,65Ref. image 

Remainder of 64 is 12So 64−12=52Remainder of 72 is 772−7=65H.C.F of 52,65Ref. image So 13 is the largest