The largest number that will divide 398,436 and 542 leaving remainders 7,11 and 15 respectively is (a) 17 (b) 11 (c) 34 (d) 45
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3
Answer:
A
Explaination:(a); [Hint. Algorithm 398 – 7 – 391; 436 – 11 = 425; 542 – 15 = 527; HCF of 391, 425, 527 = 17]
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4
Answer:
OPTION A
Hence, HCF of 391, 4250 and 527 is 17 because the greatest common factor from all the numbers is 17 only. So we can say that the largest number that will divide 398, 436 and 542 leaving remainders 7, 11 and 15 respectively is 17.
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