Question

the largest number which devides 70 and 125, leaving remainders 5 and 8 respectively, ​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

(a) Since, 5 and 8 are the remainders of 70 and 125, respectively. Thus, after subtracting these remainders from the numbers, we have the numbers 65 = (70-5),

117 = (125 – 8), which is divisible by the required number.

Now, required number = HCF of 65,117 [for the largest number]

For this, 117 = 65 × 1 + 52 [∵ dividend = divisior × quotient + remainder]

⇒ 65 = 52 × 1 + 13

⇒ 52 = 13 × 4 + 0

∴ HCF = 13

Hence, 13 is the largest number which divides 70 and 125, leaving remainders 5 amnd 8.

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