The largest number which divides 285 and 1249 leaving remainders 9 and 7 respectively is
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285-9=276
1249-7=1242
Now HCF of 276 and 1242=138 is largest required number.
Checking:
138*2=276 and 276+9=285
138*9=1242 and 1242+7=1247
1249-7=1242
Now HCF of 276 and 1242=138 is largest required number.
Checking:
138*2=276 and 276+9=285
138*9=1242 and 1242+7=1247
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