Question

the largest number which divides 318 and 739 leaving remainders 3 and 4 respectively is
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Answer 1

Answer:

this answer is 105 I think it will help you

Answer 2

Answer:

Given no.s = 318 & 739

If we should get remainder 3 & 4 respectively

then the largest no. must divide:

318-3=315

739-4=735

if we prime factorize 315 and 729:

315= 3×3×5×7

735= 3×5×7×7

so common prime factors are 3×5×7= 105

so the largest no. which divides 318 and 739 leaving a remainder 3 and 4 respectively is 105.